2t^2-30t=0

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Solution for 2t^2-30t=0 equation: 



2t^2-30t=0

a = 2; b = -30; c = 0;
Δ = b2-4ac
Δ = -302-4·2·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$


$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-30}{2*2}=\frac{0}{4}
=0
$


$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+30}{2*2}=\frac{60}{4}
=15
$

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